Header: 数学物理方法

高频公式表

2021-04-05

名书镇贴

东西慢慢加进来好了,顺便看看公式渲染的情况。

 
柱坐标系下的梯度散度旋度公式 #
(∇u)_r=∂u∂r, (∇u)_θ=1r∂u∂θ, (∇u)_z=∂u∂z(\nabla u)\_r = \frac{\partial u}{\partial r},\ (\nabla u)\_{\theta} = \frac 1 r \frac{\partial u}{\partial \theta},\ (\nabla u)\_z = \frac{\partial u}{\partial z}∇⋅A=1r∂(rAr)∂r+1r∂Aθ∂θ+∂Az∂z\nabla \cdot \mathbf{A} = \frac 1 r \frac{\partial (r A_r)}{\partial r} + \frac 1 r \frac{\partial A_{\theta}}{\partial \theta} + \frac{\partial A_z}{\partial z}∇×A=1r[∂Az∂θ−∂(rAθ)∂z]er+[∂Ar∂z−∂Az∂r]eθ+1r[∂(rAθ)∂r−∂Ar∂θ]ez\nabla \times \mathbf{A} = \frac 1 r \left[\frac{\partial A_z}{\partial \theta} - \frac{\partial (rA_{\theta})}{\partial z}\right]\mathbf{e_r} + \left[\frac{\partial A_r}{\partial z} - \frac{\partial A_z}{\partial r}\right]\mathbf{e_{\theta}} + \frac 1 r \left[\frac{\partial (rA_{\theta})}{\partial r} - \frac{\partial A_r}{\partial \theta}\right]\mathbf{e_z}
球坐标系下的梯度散度旋度公式 #
(∇u)_r=∂u∂r, (∇u)_θ=1r∂u∂θ, (∇u)_ϕ=1rsin⁡θ∂u∂ϕ(\nabla u)\_r = \frac{\partial u}{\partial r},\ (\nabla u)\_{\theta} = \frac 1 r \frac{\partial u}{\partial \theta},\ (\nabla u)\_{\phi} = \frac{1}{r \sin \theta} \frac{\partial u}{\partial \phi}∇⋅A=1r2∂(r2Ar)∂r+1rsin⁡θ∂(sin⁡θAθ)∂θ+1rsin⁡θ∂Aϕ∂ϕ\nabla \cdot \mathbf{A} = \frac{1}{r^2} \frac{\partial (r^2 A_r)}{\partial r} + \frac{1}{r \sin \theta} \frac{\partial (\sin \theta A_{\theta})}{\partial \theta} + \frac{1}{r \sin \theta} \frac{\partial A_{\phi}}{\partial \phi}∇×A=1rsin⁡θ[∂(sin⁡θAϕ)∂θ−∂Aθ∂ϕ]er+1r[1sin⁡θ∂Ar∂ϕ−∂(rAϕ)∂r]eθ+1r[∂(rAθ)∂r−∂Ar∂θ]eϕ\nabla \times \mathbf{A} = \frac{1}{r \sin \theta} \left[\frac{\partial (\sin \theta A_{\phi})}{\partial \theta} - \frac{\partial A_{\theta}}{\partial \phi}\right]\mathbf{e_r} + \frac 1 r \left[\frac{1}{\sin \theta}\frac{\partial A_r}{\partial \phi} - \frac{\partial (r A_{\phi})}{\partial r}\right]\mathbf{e_{\theta}} + \frac 1 r \left[\frac{\partial (rA_{\theta})}{\partial r} - \frac{\partial A_r}{\partial \theta}\right]\mathbf{e_{\phi}}
Leave your comments and reactions on GitHub